A cliff on the bank of a river is 300 meters hi... - JAMB Mathematics 2009 Question
A cliff on the bank of a river is 300 meters high. If the angle of depression of a point on the opposite side of the river is 60o, find the width of the river.
A
75√3m
B
100√3m
C
200√3m
D
100m
correct option: b
Tan 60o = \(\frac{300}{x}\)
x Tan 60o = 300
x√3 = 300
x = \(\frac{300}{\sqrt{3}}\) x \(\frac{\sqrt{3}}{\sqrt{3}}\)
x = \(\frac{300\sqrt{3}}{3}\) x 100\(\sqrt{3}\)
x Tan 60o = 300
x√3 = 300
x = \(\frac{300}{\sqrt{3}}\) x \(\frac{\sqrt{3}}{\sqrt{3}}\)
x = \(\frac{300\sqrt{3}}{3}\) x 100\(\sqrt{3}\)
Please share this, thanks:
Add your answer
No responses